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The value of 0.2   log514+18+116+......is

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a
4
b
log 4
c
log 2
d
log 3

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detailed solution

Correct option is A

We have, 14+18+116+…=1/41−1/2=120.2log⁡514+18+116+….=0.2log512=15 log512                                 =5−12log512=(5)−2log512=(5)log54=4


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