The value of Ltx→π4⁡1−sin⁡2xπ−4x is equal to

Ltx→π4⁡1−sin⁡2xπ−4x⋅1+sin⁡2x1+sin⁡2x=limx→π4 1−sin⁡2x(π−4x)1+sin⁡2x=Ltx→π41−cos⁡π2−2x4π4−x⋅Ltx→π4⁡11+sin⁡2x=Ltx→π4⁡2sin2⁡π4−x4π4−x⋅12 =Ltx→π42 sinπ4−xπ4−x142=14