A value of θ lying between θ=0 and θ=π/2 and satisfying the equation1+sin2θcos2θ4sin4θsin2θ1+cos2θ4sin4θsin2θcos2θ1+4sin4θ=0 is
3π/24
5π/24
11π/24
π/24
Applying R1→R1−R3,R2→R2−R3 to the given determinant we get
10−101−1sin2θcos2θ1+4sin4θ=0
⇒1+4sin4θ+cos2θ+sin2θ=0
⇒sin4θ=−1/2⇒4θ=π+π/6 or 2π−π/6 [∵0<4θ<2π]
⇒ θ=7π/24 or 11π/24