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The value of m for which one of the roots of x23x+2m=0 is double of one of the roots of x2x+m=0 is

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a
-2
b
1
c
2
d
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detailed solution

Correct option is A

Let α be the root of x2−x+m=0 and 2α be the root of x2−3x+2m=0. Then, α2−α+m=0 and 4α2−6α+2m=0Eliminating α,m2=−2m⇒m=0,m=−2

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