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The value of $\int_{0}^{1} max (e^{x}, e^{1 - x}) d x$ equals

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2(e−1)

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detailed solution

Correct option is B

∫01 maxex,e1−xdx=∫01/2 maxex,e1−xdx+∫1/21 maxex,e1−xdx=∫01/2 e1−xdx+∫1/21 exdx=−e1−x01/2+e−e1/2=−e1/2+e+e−e1/2=2e−e1/2

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The value of ∫01 maxex,e1−xdx equals

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The value of $\int_{0}^{1} max (e^{x}, e^{1 - x}) d x$ equals