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Q.

The value of 2×nC1+23×nC3+25×nC5+… is

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a

3n+(−1)n2

b

3n−(−1)n2

c

3n+12

d

3n−12

answer is B.

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Detailed Solution

(1+2)n−(1−2)n=2 nC1×2+nC3×23+nC5×25+…∴ nC1×2+nC3×23+nC5×25+…=3n−(−1)n2
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