The value of nC1+n+1C2+n+2C3+⋯+n+m−1Cm is equal to
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a
m+nCn−1
b
m+nCn−1
c
mC1+m+1C2+m+2C3+⋯+m+n−1Cn
d
m+nCm−1
answer is A.
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Detailed Solution
nC1+n+1C2+n+2C3+⋯+n+m−1Cm =nCn−1+n+1Cn−1+n+2Cn−1+⋯+n+m−1Cn−1= Coefficient of xn−1 in (1+x)n+(1+x)n+1+(1+x)n+2+⋯+(1+x)n+m−1= Coefficient of xn−1 in (1+x)n(1+x)m−1(1+x)−1= Coefficient of xn−1 in (1+x)m+n−(1+x)nx= Coefficient of xn in (1+x)m+n−(1+x)n=m+nCn−1Similarly, we can prove mC1+m+1C2+m+2C3+⋯+m+n−1Cn=m+nCm−1