The value of ∑n=1100∫n−1nex−xdx, where x is the greatest integer less than or equal to x, is :
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a
1001−e
b
1001+e
c
100e
d
100e-1
answer is D.
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Detailed Solution
∑n=1100∫n−1nex−xdx=∑n=1100∫n-1nexdx= ∑n=1100∫01exdx { formula ∫mTnTf(x)dx=n-m ∫0Tf(x)dx where T= period of f(x) } = ∑n=1100∫01exdx { x is periodic function with period 1 } =∑n=1100e-1 =100e-1