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Q.

The value of ∑n=1100∫n−1nex−xdx, where x is the greatest integer less than or equal to x, is  :

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a

1001−e

b

1001+e

c

100e

d

100e-1

answer is D.

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Detailed Solution

∑n=1100∫n−1nex−xdx=∑n=1100∫n-1nexdx= ∑n=1100∫01exdx             {  formula  ∫mTnTf(x)dx=n-m ∫0Tf(x)dx    where T= period of f(x)   }                              =     ∑n=1100∫01exdx                                                 {    x  is periodic function with period 1   }                               =∑n=1100e-1                                      =100e-1
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