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The value of $n$ for which $704 + \frac{1}{2} (704) + \frac{1}{4} (704) + \dots$ up $n$ terms $= 1984 - \frac{1}{2} (1984) + \frac{1}{4} (1984) - . . . .$ up to $n$ terms is

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Correct option is A

According to the given condition(704) 1−12n=(1984)(2)31−(−1)n2n(2)⇒ 128=21122n−1984(−1)n2nIf n is odd, we get 2n=32 or n=5If n is even, we get 128=128/2n⇒n=0.

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The value of n for which 704+12(704)+14(704)+…up n terms =1984−12(1984)+14(1984)-.... up to n terms is

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The value of $n$ for which $704 + \frac{1}{2} (704) + \frac{1}{4} (704) + \dots$ up $n$ terms $= 1984 - \frac{1}{2} (1984) + \frac{1}{4} (1984) - . . . .$ up to $n$ terms is