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The value of 11+nsin2nx can be n∈N

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a

-1

b

0

c

1

d

∞

answer is B.

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Detailed Solution

Case I: x≠mπ m is an integer limx→∞ 11+nsin2nx=1∞=0Case II: x=mπ m is an integer limx→1 11+n sin2nx=11=1

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