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The value of parameter, for which the function $f (x) = 1 + α x, \neq 0$ is the inverse of itself is

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Correct option is B

f−1(x)=f(x) x−1α=1+α x⇒α=−1

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The value of parameter, for which the function f(x)=1+α x, ≠0 is the inverse of itself is

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The value of parameter, for which the function $f (x) = 1 + α x, \neq 0$ is the inverse of itself is