The value of ∑r=020C6 50-r is equal to:
51C7− 30C7
50C6− 30C6
50C7− 30C7
51C7+ 30C7
∑r=020C6 50-r =50C6+49C6+......+31C6+C6 + 30 30C7−30C7
=51C7−30C7