Q.

The value of ∑r=110 r2⋅ 26Cr 26Cr−1 is

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answer is 1100.

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Detailed Solution

S=∑r=110 r2⋅ 26Cr 26Cr−1=∑r=110 r2⋅27−rr=∑r=110 27r−r2=27r(r+1)2−r(r+1)⋅(2r+1)6Putting r = 10∴ S=27(5)(11)−(5)(11)(7)=1100
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