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Q.

The value of ∑r=010 (r)20Cr is equal to

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a

20218+19C10

b

10218+19C10

c

20218+19C11

d

10218+19C11

answer is A.

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Detailed Solution

∑r=010 (r)20Cr=∑r=110 20×19Cr−1 (ncr=nr (n-1)c(r-1) )=20 19C0+19C1+…+19C10=20 19C0+19C1+…+19C10=2012×219+19C10=20218+19C10

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