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Q.

The value of ∑r=15r Cr   nCr-1   n=

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a

5(n-3)

b

5(n-2)

c

5n

d

5(2 n-9)

answer is B.

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Detailed Solution

r⋅Cn,rCn,r−1=r⋅n!n−r!r!⋅r−1!n−r+1!n!=n−r+1∑r=15r⋅Cn,rCn,r−1=n+n−1+n−2+n−3+n−4=5n−10
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