Q.
The value of S=∑k=16 sin2πk7−icos2πk7
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a
-1
b
0
c
-i
d
i
answer is D.
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Detailed Solution
sin2πk7−icos2πk7 =−icos2πk7+isin2πk7=−iωk[ De Moivre's Theorem ]where ω=cos2π7+isin2π7Note that ω7=1∴ S=−i∑k=16 ωk=−iω1−ω61−ω=−iω−ω71−ω=−i(ω−1)1−ω=i
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