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Questions  

The value of S=k=16sin2πk7icos2πk7

a
-1
b
0
c
-i
d
i

detailed solution

Correct option is D

sin⁡2πk7−icos⁡2πk7      =−icos⁡2πk7+isin⁡2πk7=−iωk[ De Moivre's Theorem ]where  ω=cos⁡2π7+isin⁡2π7Note that ω7=1∴  S=−i∑k=16 ωk=−iω1−ω61−ω=−iω−ω71−ω=−i(ω−1)1−ω=i

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