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The value of a in (π,0) satisfying  sinα+α2αcos2xdx=0 is

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a
−π/2
b
−π
c
−π/3
d
−π/4

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detailed solution

Correct option is C

sin⁡α+∫a2a cos⁡2xdx=0⇒sin⁡α+12(sin⁡4α−sin⁡2α)=0⇒sin⁡α[1+cos⁡(3α)]=0As −π<α<0,sin⁡α≠0 thereforecos⁡(3α)=−1⇒α=−π/3.


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