The value of a in (−π,0) satisfying sinα+∫α2α cos2xdx=0 is
−π/2
−π
−π/3
−π/4
sinα+∫a2a cos2xdx=0⇒sinα+12(sin4α−sin2α)=0⇒sinα[1+cos(3α)]=0
As −π<α<0,sinα≠0 therefore
cos(3α)=−1⇒α=−π/3.