The value of ∫secxdxsin(2x+θ)+sinθ is
(tanx+tanθ)secθ+C
2(tanx+tanθ)secθ+C
2(sinx+tanθ)secθ+C
none of these
The given integrals can be written as
∫secxdx2sin(x+θ)cosx=12∫sec3/2xdxsinxcosθ+sinθcosx=12∫sec2xdxtanxcosθ+sinθ=12∫dttcosθ+sinθ=22tcosθ+sinθ+C=2(tanxsecθ+tanθsecθ)+C