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Questions  

The value of  sin1[cos{cos1(cosx)+sin1(sinx)}]where  x(π2,π)is equal to 

a
π2
b
c
π
d
-π2

detailed solution

Correct option is D

sin−1cos{cos−1(cosx)+sin−1(sinx)}=sin−1[cos(x+π−x)] ∵sin-1sinx=sin-1sinπ-x=π-x             ∵x∈π2,π⇒π2

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