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Questions  

The value of sin1cotsin1234+cos1124+sec12, is 

a
π4
b
π6
c
0
d
π2

detailed solution

Correct option is C

sin−1⁡cot⁡sin−1⁡2−34+cos−1⁡124+sec−1⁡2=sin−1⁡cot⁡sin−1⁡3−122+cos−1⁡32+sec−1⁡2=sin−1⁡cot⁡π12+π6+π4=sin−1⁡cot⁡π2=sin−1⁡0=0

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