The value of sin-1cotsin-12-34+cos-1124+sec-12 is equal to
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a
1
b
0
c
-1
d
2
answer is B.
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Detailed Solution
Given that sin-1cotsin-12-34+cos-1124+sec-12 Consider, 2-34=4-238=(3-1)28=3-122 Now, sin-12-34=sin-13-122=π1215° Also cos-1124=cos-132=π6sec-12=π4∴sin−1cotsin−12−34+cos−1124+sec−12=sin−1cotπ12+π6+π4=sin−1cotπ2=sin−10=0