The value of $$sin$$−$$1$$$$π$$e Where. is g.i. $$f=k$$, then $$3k=$$

We have π$$=3.14$$ ⇒π$$=3Also$$ $$e=2.718$$ ⇒$$e=2$$∴$$Sin-1$$$$π$$$$e=Sin-132=$$π$$3=k$$⇒$$3k=$$π

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The value of $\sin^{- 1} (\frac{\sqrt{[π]}}{[e]}) (W h e r e [.] i s g . i . f) = k$ , then $3 k =$

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Solution

$\begin{array}{l} W e h a v e π = 3.14 \Rightarrow [π] = 3 \\ A l s o e = 2.718 \Rightarrow [e] = 2 \\ ∴ S i n^{- 1} (\frac{\sqrt{[π]}}{[e]}) = {Sin}^{- 1} (\frac{\sqrt{3}}{2}) = \frac{π}{3} = k \Rightarrow 3 k = π \end{array}$

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