The value of ∫0π sin(n+1/2)xsin(x/2)dx(n∈N) is
π
2π
3π
none of these
We have,
2sinx212+cosx+cos2x+…+cosnx=sinx2+2sinx2cosx+2sinx2cos2x+…+2sinx2,cos nx
=sinx2+sin3x2−sinx2+sin5x2−sin3x2+…+sinn+12x−sinn−12x=sinn+12x
12+cosx+cos2x+…+cosnx=sinn+12x2sin(x/2)
⇒ ∫0π sinn+12xsin(x/2)dx
=2∫0π 12dx+∫0π cosxdx+…+∫0π cosnxdx=2π2+sinx0π+…+sinnxn0π=π