First slide
Evaluation of definite integrals
Question

The value of 0πsin(n+1/2)xsin(x/2)dx(nN) is

Moderate
Solution

We have,

2sinx212+cosx+cos2x++cosnx=sinx2+2sinx2cosx+2sinx2cos2x++2sinx2,cos nx

=sinx2+sin3x2sinx2+sin5x2sin3x2++sinn+12xsinn12x=sinn+12x

12+cosx+cos2x++cosnx=sinn+12x2sin(x/2)

 0πsinn+12xsin(x/2)dx

=20π12dx+0πcosxdx++0πcosnxdx=2π2+sinx0π++sinnxn0π=π

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