The value of sin−1⁡(sin⁡10) is

We know that sin−1⁡(sin⁡θ)=θ, if −π2≤θ≤π2Here, θ=10 radians which does not lie between −π2 and π2But, 3π−θ i.e. 3π−10 lies between −π2 and π2Also sin⁡(3π−10)=sin⁡10sin−1⁡(sin⁡10)=sin−1⁡(sin⁡(3π−10))=3π−10