The value of sin−1(sin10) is
3π−10
10−3π
3π+10
4π−10
We know that sin−1(sinθ)=θ, if −π2≤θ≤π2
Here, θ=10 radians which does not lie between −π2 and π2
But, 3π−θ i.e. 3π−10 lies between −π2 and π2
Also sin(3π−10)=sin10sin−1(sin10)=sin−1(sin(3π−10))=3π−10