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Questions  

The value of sin1(sin10) is

a
3π−10
b
10−3π
c
3π+10
d
4π−10

detailed solution

Correct option is A

We know that sin−1⁡(sin⁡θ)=θ, if −π2≤θ≤π2Here, θ=10 radians which does not lie between −π2 and π2But, 3π−θ i.e. 3π−10 lies between −π2 and π2Also sin⁡(3π−10)=sin⁡10sin−1⁡(sin⁡10)=sin−1⁡(sin⁡(3π−10))=3π−10

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