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Questions  

The value of sinπ2sin132 is 

a
32
b
-32
c
12
d
-12

detailed solution

Correct option is C

sin⁡π2−sin−1⁡−32=cos⁡sin−1⁡−32 =cos⁡cos−1⁡1−34=cos⁡cos−1⁡12=12

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