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The value of $\sin (4 \tan^{- 1} \frac{1}{3}) - \cos (2 \tan^{- 1} \frac{1}{7})$ is

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Correct option is B

sin⁡4tan−1⁡13=2sin⁡2tan−1⁡13cos⁡2tan−1⁡13=2sin⁡tan−1⁡34cos⁡tan−1⁡342tan−1⁡13=tan−1⁡2⋅131−132=tan−1⁡34 =2⋅35⋅45=2425Also, cos⁡2tan−1⁡17=cos⁡tan−1⁡724=2425∴ The given expression = 0

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The value of sin⁡4tan−1⁡13−cos⁡2tan−1⁡17 is

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The value of $\sin (4 \tan^{- 1} \frac{1}{3}) - \cos (2 \tan^{- 1} \frac{1}{7})$ is