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The value of sinxcosxsin2x1/2dx is

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a
log⁡|(sin⁡x+cos⁡x)+sin⁡2x|+C
b
−log⁡|(sin⁡x+cos⁡x)+sin⁡2x−1/2|+C
c
−12log⁡|(sin⁡x+cos⁡x)+sin⁡2x−1/2|+C
d
none of these

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detailed solution

Correct option is B

The given integral can be written as∫sin⁡x−cos⁡x(sin⁡x+cos⁡x)2−3/2dx=−∫dtt2−3/2(t=sin⁡x+cos⁡x)=−log⁡t+t2−3/2+C=−log⁡|sin⁡x+cos⁡x+sin⁡2x−1/2|+C


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