Questions
The value of is
detailed solution
Correct option is B
Put x1/3=θ so that dx=3θ2dθ∴I=3∫θ2sinθdθ=−3θ2cosθ+6∫θcosθdθ=−3θ2cosθ+6θsinθ−6∫sinθdθ=32−θ2cosθ+6θsinθ+C.Similar Questions
is equal to
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