The value of ∫sinx3dx is
2−x2/3cosx1/3+2x1/3sinx1/3+C
32−x2/3cosx1/3+2x1/3sinx1/3+C
32−x2/3sinx1/3−2x1/3cosx1/3+C
none of these
Put x1/3=θ so that dx=3θ2dθ
∴I=3∫θ2sinθdθ=−3θ2cosθ+6∫θcosθdθ=−3θ2cosθ+6θsinθ−6∫sinθdθ=32−θ2cosθ+6θsinθ+C.