The value of the sum ∑i=120 i1i+1i+1+1i+2+…+120 is
100
105
110
115
∑i=120 i1i+1i+1+1i+2+…+120=11+12+⋯+120 +212+13+⋯+120+313+⋯+120+20120=(1)(1)+12(1+2)+13(1+2+3)+⋯
+120(1+2+⋯+20)
=∑k=120 1k(1+2+⋯+k)=12∑k=120 (k+1)=12⋅12(20)(2+21)=115