First slide
Sigma operation series
Question

The value of the sum i=120i1i+1i+1+1i+2++120 is

Moderate
Solution

i=120i1i+1i+1+1i+2++120=11+12++120 +212+13++120+313++120+20120=(1)(1)+12(1+2)+13(1+2+3)+

                                   +120(1+2++20)

=k=1201k(1+2++k)=12k=120(k+1)=1212(20)(2+21)=115

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