The value of tan 821∘2, is

We have,tan⁡8212∘=cot⁡712∘=cos⁡712∘sin⁡712∘=2cos2⁡71∘22sin⁡71∘2cos⁡71∘2=1+cos⁡15∘sin⁡15∘=1+3+1223−1=22+3+13−1=(22+3+1)(3+1)(3+1)(3−1)=26+22+3+3+3+12=6+2+4+3=2+3+4+6