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Questions  

The value of tan1a(a+b+c)bc+tan1b(a+b+c)ca+tan1c(a+b+c)ab is

a
π4
b
π2
c
π
d
none of these

detailed solution

Correct option is C

The given expression can be written astan−1⁡aa+b+cabc+tan−1⁡ba+b+cabc+tan−1⁡ca+b+cabc=tan−1⁡(ay)+tan−1⁡(by)+tan−1⁡(cy)where, y=a+b+cabc=tan−1⁡ay+by+cy−abcy31−aby2−bcy2−acy2=tan−1⁡ya+b+c−abcy21−y2(ab+bc+ca)=tan−1⁡0=0 or π

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