The value of tan12cos−153, is
3+52
3+5
12(3−5)
none of these
Let cos−153=α. Then,
cosα=53, Where 0<α<π2
Now,
tanα2=1−cosα¯1+cosα⇒ tanα2=1−5/31+5/3
= tanα2=3−53+5=(3−5)29−5=12(3−5)
⇒ tan12cos−153=3−52