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Questions  

The value of tancos127π2 is

a
235
b
23
c
15
d
45

detailed solution

Correct option is A

=tan⁡cos−1⁡−27−π2=tan⁡π−cos−1⁡27−π2 =tan⁡π2−cos−1⁡27=tan⁡sin−1⁡27=tan⁡tan−1⁡235=235

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