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Questions  

The value of tan14sin1638 is 

a
17
b
27
c
78
d
18

detailed solution

Correct option is A

Let sin−1⁡638=θ. Then , sin⁡θ=638 and cos⁡θ=18. Now,cos⁡θ=18⇒2cos2⁡θ2−1=18⇒cos2⁡θ2=916⇒cos⁡θ2=34∴tan⁡14sin−1⁡638=tan⁡θ4=1−cos⁡θ21+cos⁡θ2=1−341+34=17

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