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Questions  

The value of tan11+tan12+tan13, is 

a
0
b
1
c
π
d

detailed solution

Correct option is C

We have,        tan−1⁡1+tan−1⁡2+tan−1⁡3=  tan−1⁡1+π+tan−1⁡2+31−2×3=  tan−1⁡1+π+tan−1⁡(−1)=π

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