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Questions  

The value of tan1(12tan2A)+tan1(cotA)+tan1(cot3A) , for 0<A<π/4 , is

a
tan−12
b
tan−1(cotA)
c
4tan−1(1)
d
2tan−1(2)

detailed solution

Correct option is C

For  01⇒(cotA)(cot3A)>1⇒tan−1(12tan2A)+tan−1(cotA)+tan−1(cot3A)=tan−1(tanA1−tan2A)+π+tan−1(cotA+cot3A1−cot4A)=tan−1(tanA1−tan2A)+π+tan−1(cotA1−cot2A)=tan−1(tanA1−tan2A)+π+tan−1(tanAtan2A−1)=π=4(π/4)=4tan−1(1)

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