First slide
Properties of ITF
Question

The value of tan1(12tan2A)+tan1(cotA)+tan1(cot3A) , for 0<A<π/4 , is

Moderate
Solution

For  0<A<π/4,cotA>1(cotA)(cot3A)>1

tan1(12tan2A)+tan1(cotA)+tan1(cot3A)

=tan1(tanA1tan2A)+π+tan1(cotA+cot3A1cot4A)=tan1(tanA1tan2A)+π+tan1(cotA1cot2A)=tan1(tanA1tan2A)+π+tan1(tanAtan2A1)=π=4(π/4)=4tan1(1)

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