Questions
The value of (1.00 2)12 up to fourth place of decimal is
a
1.0242
b
1.0245
c
1.0004
d
1.0254
detailed solution
Correct option is A
We have, (1.002)12 or it can be rewritten as (1 + 0.00212⇒ (1.002)12=1+12C1(0.002)+12C2(0.002)2+12C3(0.002)3+…... we want the answer up to 4 decimal places and as suchwe have left further expansion.∴ (1.002)12=1+12(0.002)+12⋅111⋅2(0.002)2+12⋅11⋅101⋅2⋅3(0.002)3+… =1+0.024+2.64×10−4+1.76×10−6+…...==1.0242Talk to our academic expert!
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