The value of (1.00 2)12 up to fourth place of decimal is

We have, (1.002)12 or it can be rewritten as (1 + 0.00212⇒ (1.002)12=1+12C1(0.002)+12C2(0.002)2+12C3(0.002)3+…... we want the answer up to 4 decimal places and as suchwe have left further expansion.∴ (1.002)12=1+12(0.002)+12⋅111⋅2(0.002)2+12⋅11⋅101⋅2⋅3(0.002)3+… =1+0.024+2.64×10−4+1.76×10−6+…...==1.0242