The value of ‘a’ for which the equations 3x−y+az=1,2x+y+z=2,x+2y−az=−1fail to have unique solution
72
-72
27
-27
the condition for a non-homogeneous system fails to have a unique solution is A=0
⇒A=3 −1 a2 1 11 2 −a=0⇒3−a−2+1−2a−1+a4−1=0
⇒-3a-6-2a-1+3a=0⇒-7=2a⇒a=-7/2