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The value of x=21/441/881/16161/32 is 

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a
2
b
3/2
c
1
d
1/2

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detailed solution

Correct option is A

x=2Swhere S=14+28+316+432+…⇒12S=18+216+332+…Subtracting, we get 12S=14+18+116+132+…=1/41−1/2=14×2=12⇒    S=1.∴    x=2


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The sum to infinity of the series S=1+23+632+1033+1434+is


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