The value of ∫$$04$$ $$32x+1$$ dx is

Correct option is 4none of these

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The value of $\int_{0}^{4} 3^{\sqrt{2 x + 1}} d x$ is

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6log⁡ 313−4log⁡ 3

66log⁡ 3

6log⁡ 313−5log⁡ 3

none of these

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detailed solution

Correct option is D

Putting 2x+1=t2, we have dx=t dt, so ⇒∫04 32x+1dx=∫13 3ttdt=t⋅3tlog⁡ 313−1log⁡ 3∫13 3tdt=(3)⋅33−3log⁡ 3−1(log⁡ 3)233−31=78log⁡ 3−24(log⁡ 3)2

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The value of ∫04 32x+1 dx is

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The value of $\int_{0}^{4} 3^{\sqrt{2 x + 1}} d x$ is