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The value of 1/212xsin1xcos1xdx is

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a
sin 1
b
cos 1
c
2 sin 1
d
none of these

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detailed solution

Correct option is D

∫1/21 2xsin⁡1x−cos⁡1x=x2sin⁡1x1/21−∫1/21 x2cos⁡1x-1x2−∫1/21 cos⁡1xdx


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