The value of x for which cos−1(cos4)>3x2−4x is
0,2+6π−83
2−6π−83,0
(-2, 2)
2−6π−83,2+6π−83
Now, cos−1(cos4)=cos−1{cos(2π−4)}=2π−4 ⇒2π−4>3x2−4x⇒3x2−4x−(2π−4)<0⇒2−6π−83<x<2+6π−83