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The value of $\int_{0}^{1} x^{2} (1 - x)^{9} d x$ is

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Correct option is D

∫01 x2(1−x)9dx=−∫10 (1−t)2t9dt(1−x=t)=∫01 1−t2−2tt9dt=t1010+t1212−2t111101=110+112−211=1660

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The value of ∫01 x2(1−x)9dx is

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The value of $\int_{0}^{1} x^{2} (1 - x)^{9} d x$ is