The value of ∫01 x2(1−x)9dx is
1610
1630
1640
1660
∫01 x2(1−x)9dx=−∫10 (1−t)2t9dt(1−x=t)=∫01 1−t2−2tt9dt=t1010+t1212−2t111101=110+112−211=1660