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The value of 01x3(1x)11dx is equal to

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a
111+312+313+114
b
−111+312−313+114
c
813
d
111−312+314−114

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detailed solution

Correct option is D

Given integral is equal to ∫01 (1−x)3(1−(1−x))11dx=∫01 x11(1−x)3dx=∫01 x111−3x+3x2−x3dx=∫01 x11−3x12+3x13−x14dx=111−312+313−114


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