First slide

Introduction to definite integration

Question

The value of $\int_{0}^{1} [1 - \frac{x}{1!} + \frac{x^{2}}{2!} - \frac{x^{3}}{3!} + ............. {(- 1)}^{n} \frac{x^{n}}{n!} . . .] e^{2 x} d x$ is

Easy

A

0
B

$e - 1$
C

1
D

$e$

Solution

$\int_{0}^{1} e^{- x} . e^{2 x} d x = \int_{0}^{1} e^{x} d x = e - 1$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App