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Q.

Value of ∫15 {x+2x−1+x−2(x−1)}dx is

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a

83

b

163

c

323

d

343

answer is D.

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Detailed Solution

x+(2x−1)=|x−1+1|⇒x−2x−1=|x−1−1|I=∫12 2dx+∫25 2x−1dx=2⋅1+2⋅(x−1)3/2⋅2325=2+283=343
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