The value of ∫x+1x3/2x2−1x2dx, is
23x+1x3/2+C
25x+1x5/2+C
2x+1x1/2+C
none of these
We have,
I=∫x+1x3/2x2−1x2dx⇒ I=∫x+1x3/2dx+1x=25x+1x5/2+C