The value of ∫−π/2π/2 x3+xcosx+tan5x+1dx is
0
2
π
1
Let
I=∫−π/2π/2 x3+xcosx+tan5x+1dx ⇒I=∫−π/2π/2 x3dx+∫−π/2π/2 xcosxdx+∫−π/2π/2 tan5xdx+∫−π/2π/2 1dx
we know that,∫−aa f(x)dx=2∫0a f(x)dx, if f(x) is even 0, if f(x) is odd
∴ l=0+0+0+2∫0π/2 1dx∵x3,xcosx and tan5(x) are odd functions
∴ I=2[x]0π/2=2π2=π