The value of ∫−π/2π/2 x3+xcos⁡x+tan5⁡x+1dx is

Let  I=∫−π/2π/2 x3+xcos⁡x+tan5⁡x+1dx ⇒I=∫−π/2π/2 x3dx+∫−π/2π/2 xcos⁡xdx+∫−π/2π/2 tan5⁡xdx+∫−π/2π/2 1dxwe know that,∫−aa f(x)dx=2∫0a f(x)dx, if f(x) is even 0, if f(x) is odd ∴  l=0+0+0+2∫0π/2 1dx∵x3,xcos⁡x and tan5⁡(x) are odd functions ∴ I=2[x]0π/2=2π2=π