The values of f(x)=3sin(π216−x2) lie in the interval

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(0, 32)

(−32, 32)

[0, 32]

[−32, 32]

answer is C.

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Detailed Solution

π216−x2≥0 ⇒−π4≤×≤π4 ∴Df=[−π4,π4]f(0)=3sinπ4=12 fπ4=3sin0=0 range is 0, 12

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