The values of k for which the inequality kcos2x−kcosx+1≥0,∀x∈(−∞,∞) holds is
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a
k<−12
b
k>4
c
−12≤k≤4
d
12≤k≤5
answer is C.
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Detailed Solution
kcos2x−kcosx+1≥0∀x∈(−∞,∞)⇒ kcos2x−cosx+1≥0 →ibut cos2x−cosx=cosx−122−14⇒−14≤cos2x−cosx≤2Now, from (i), we get 2k+1≥0⇒k≥−12 Also, −k4+1≥0⇒ k≤4⇒ −12≤k≤4